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### is_convertible

    template <class From, class To>
    struct is_convertible : public true_type-or-false_type {};

Inherits: If an imaginary rvalue of type `From` is convertible to type `To` then inherits from true_type, otherwise inherits from false_type.

Type From must not be an incomplete type.

Type To must not be an incomplete, or function type.

No types are considered to be convertible to array types or abstract-class types.

This template can not detect whether a converting-constructor is `public` or not: if type `To` has a `private` converting constructor from type `From` then instantiating `is_convertible<From, To>` will produce a compiler error. For this reason `is_convertible` can not be used to determine whether a type has a `public` copy-constructor or not.

This template will also produce compiler errors if the conversion is ambiguous, for example:

    struct A {};
    struct B : A {};
    struct C : A {};
    struct D : B, C {};
    // This produces a compiler error, the conversion is ambiguous:
    bool const y = boost::is_convertible<D*,A*>::value;

C++ Standard Reference: 4 and 8.5.

Compiler Compatibility: All current compilers are supported by this trait.

Header: `#include <boost/type_traits/is_convertible.hpp>` or `#include <boost/type_traits.hpp>`

Examples:

> `is_convertible<int, double>` inherits from `true_type`.

> `is_convertible<const int, double>::type` is the type `true_type`.

> `is_convertible<int* const, int*>::value` is an integral constant expression that evaluates to true.

> `is_convertible<int const*, int*>::value` is an integral constant expression that evaluates to false: the conversion would require a `const_cast`.

> `is_convertible<int const&, long>::value` is an integral constant expression that evaluates to true.

> `is_convertible<int, int>::value` is an integral constant expression that evaluates to true.

> `is_convertible<T, T>::value_type` is the type `bool`.