Function: lcm
Section: number_theoretical
C-Name: glcm0
Prototype: GDG
Help: lcm(x,{y}): least common multiple of x and y, i.e. x*y / gcd(x,y).
Description:
 (int, int):int lcmii($1, $2)
 (gen):gen      glcm0($1, NULL)
 (gen, gen):gen glcm($1, $2)
Doc: least common multiple of $x$ and $y$, i.e.~such
 that $\lcm(x,y)*\gcd(x,y) = \text{abs}(x*y)$. If $y$ is omitted and $x$
 is a vector, returns the $\text{lcm}$ of all components of $x$.

 When $x$ and $y$ are both given and one of them is a vector/matrix type,
 the LCM is again taken recursively on each component, but in a different way.
 If $y$ is a vector, resp.~matrix, then the result has the same type as $y$,
 and components equal to \kbd{lcm(x, y[i])}, resp.~\kbd{lcm(x, y[,i])}. Else
 if $x$ is a vector/matrix the result has the same type as $x$ and an
 analogous definition. Note that for these types, \kbd{lcm} is not
 commutative.

 Note that \kbd{lcm(v)} is quite different from
 \bprog
 l = v[1]; for (i = 1, #v, l = lcm(l, v[i]))
 @eprog\noindent
 Indeed, \kbd{lcm(v)} is a scalar, but \kbd{l} may not be (if one of
 the \kbd{v[i]} is a vector/matrix). The computation uses a divide-conquer tree
 and should be much more efficient, especially when using the GMP
 multiprecision kernel (and more subquadratic algorithms become available):
 \bprog
 ? v = vector(10^4, i, random);
 ? lcm(v);
 time = 323 ms.
 ? l = v[1]; for (i = 1, #v, l = lcm(l, v[i]))
 time = 833 ms.
 @eprog